Pressure Head (h = P/ρg)

h = \frac{P}{\rho g}

h =

P =

ρ =

Enter your known values, leave one input blank, and solves for the missing one. Try different units for next level excitement!

Constant used — built into this formula, no need to enter

g_{n} = 9.80665\ \text{m/s}^{2}

Standard acceleration of gravity · exact

Learning zone

Hydraulic engineers speak in meters and feet of head rather than pascals, because head translates directly into the geometry of tanks and towers. One atmosphere (101.325 kPa) of water pressure is 101325/(1000 × 9.80665) ≈ 10.33 m of head — the reason no suction pump on Earth can lift water more than about 10 m, and why water towers stand tall: every 10 m of elevation banks another atmosphere of distribution pressure.

Pressure Head (h = P/ρg)

h = \frac{P}{\rho g}

Where

$h$ = Pressure head
$P$ = Pressure
$\rho$ = Fluid density

Missing one of these? Work it out first, then come back

Pressure head — Hydraulic Power (P = ρgQh), Net Positive Suction Head Available (NPSHa)
Pressure — Pressure (P = F/A), Ideal Gas Law
Fluid density — Dynamic Pressure (q = ½ρv²), Buoyant Force (Archimedes' Principle)

Part of this formula set

Heads in a piping system

6 formulasPressure head, velocity head, static fill pressure and total dynamic head — the feet of water a pump and a gauge are each talking about.