Active Thrust on a Retaining Wall

Pa=12 Ka γ H2P_a = \tfrac{1}{2}\,K_a\,\gamma\,H^{2}

Worked example: Ka 0.30, γ 18 kN/m³, H 5 m → Pa = 67 500 N/m — press Try an example to run it live, then adjust anything.

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Active Thrust on a Retaining Wall explained

KaγHPa

Active pressure grows linearly with depth, so the pressure diagram on a wall retaining dry granular fill is a triangle of height H and base KaγHK_a \gamma H. Its area — the total thrust per metre of wall — is 12KaγH2\tfrac{1}{2} K_a \gamma H^2, and because the diagram is triangular the resultant acts at H/3 above the base, not at mid-height. A 5 m wall with KaK_a = 0.30 and γ = 18 kN/m³ takes PaP_a = 0.5 × 0.30 × 18 × 25 = 67.5 kN per metre of wall, applied 1.67 m up.

The trap is the square. Thrust goes as H², and the overturning moment as H³, so a wall that is 20% taller than planned carries 44% more force and 73% more moment. The second and far more dangerous trap is water. Saturate the backfill and you replace γ with γ′ ≈ 9.7 kN/m³ but add a full hydrostatic triangle at 9.81 kN/m³ with a coefficient of 1.0, roughly tripling the total thrust. Almost every retaining wall that has ever fallen over did so after rain, with a blocked weep hole. Drain the backfill, and drain it with free-draining stone and a filter, not with hope.

Active Thrust on a Retaining Wall formula

Pa=12 Ka γ H2P_a = \tfrac{1}{2}\,K_a\,\gamma\,H^{2}
Where
  • PaP_a= Active thrust per metre of wall (N/m)
  • KaK_a= Active earth pressure coefficient
  • γ\gamma= Unit weight of backfill (kN/m³)
  • HH= Height of wall (m)

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