Reactive Power (Power Triangle)

Q=S2P2Q = \sqrt{S^{2} - P^{2}}

Enter your known values, leave one input blank, and solves for the missing one. Try different units for next level excitement!

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Real power P and reactive power Q are 90° apart, so they add like the legs of a right triangle with apparent power S as the hypotenuse: S² = P² + Q². A load pulling 10 kVA while doing 8 kW of work is carrying √(10² − 8²) = 6 kvar of reactive burden — the classic 3-4-5 triangle in electrical dress. Vars are watts dimensionally, so enter kvar and kVA in the kW fields here.

Reactive power does no net work over a cycle; it is energy borrowed to build a magnetic field and returned half a cycle later. The borrowing is not free — the round trip flows as real current through your conductors and the utility's transformers. That is why the fix is local: put capacitors near the motor and the vars shuttle between motor and capacitor instead of travelling back to the substation.

Reactive Power (Power Triangle)
Q=S2P2Q = \sqrt{S^{2} - P^{2}}
Where
  • QQ= Reactive power (var)
  • SS= Apparent power (VA)
  • PP= Real power