Regular Tetrahedron Volume

Also known as volume of a tetrahedron · triangular pyramid volume

V=s362V = \frac{s^3}{6\sqrt{2}}

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The regular tetrahedron is the simplest of the five Platonic solids: four vertices, six equal edges, four equilateral faces, and no way to make anything simpler in three dimensions. Its volume from the edge alone is V=s3/(62)V = s^3/(6\sqrt{2}), equivalently s32/12s^3\sqrt{2}/12, which works out to only about 11.8 percent of the cube built on the same edge. It is a startlingly empty shape for its footprint.

A neat way to see where the constant comes from: take a cube of side aa and connect four alternating corners. The result is a regular tetrahedron of edge a2a\sqrt{2}, and the four corner pieces you cut away each have volume a3/6a^3/6, leaving a3/3a^3/3 behind. Substituting s=a2s = a\sqrt{2} reproduces the formula exactly.

Tetrahedra show up wherever rigidity matters, because a triangle cannot be deformed without changing a side length and a tetrahedron inherits that stubbornness in three dimensions. Space frames, geodesic structures, and the carbon bonds in a diamond lattice all lean on it.

Regular Tetrahedron Volume
V=s362V = \frac{s^3}{6\sqrt{2}}
Where
  • VV= Volume
  • ss= Edge length
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