Sound Intensity (I = P/A)

I=PAI = \frac{P}{A}
sig figs

Worked example: 100 W over 50 m^2 → I = 2 W/m^2. Press Try an example to run it live, then adjust anything.

Enter your known values, leave one input blank, and solves for the missing one. Tap a variable’s symbol to see what it means, with a typical value. Change any unit and the answer follows.

Where Sound Intensity (I = P/A) fits

Your answer feeds
In these toolkits

See also

Inverse-Square Law for Sound: Both use sound intensity and acoustic power.Decibel Sound Level: Both use sound intensity.Sound Transmission Loss: Both use sound intensity.
Here the solver did the work. Could you?

How loud is loud →

Grade 11Grade 11 Physics

Test your skills in the Exam Room: new numbers every attempt. Free lessons for students, no sign-up, just pure learning.

See your Report Card
Learning zone

Sound Intensity (I = P/A) explained

PIA

Intensity measures how concentrated a sound's energy is: the acoustic power crossing each square meter of surface. A rock band's loudspeaker stack might radiate 100 W of acoustic power; spread that over the 50 m² face of a mosh pit and the crowd absorbs 2 W/m²: painfully loud, about 123 dB. The same 100 W spread across a 5000 m² festival field ten times farther back drops to a comfortable 0.02 W/m².

What makes hearing remarkable is the range this formula spans. The faintest sound a healthy ear detects carries about 10⁻¹² W/m², a millionth of a millionth of a watt per square meter, while the threshold of pain sits near 1 W/m², a trillion times greater. A whisper delivering 10⁻¹⁰ W to your 60 mm² eardrum is moving it a distance smaller than the diameter of a hydrogen atom.

Sound Intensity (I = P/A) formula

I=PAI = \frac{P}{A}
Where
  • II= Sound intensity (W/m²)
  • PP= Acoustic power (W)
  • AA= Area (m²)
Revised 16 October 2026
Cite this page

formula.expert. (2026, October 16). Sound Intensity (I = P/A) Formula & Calculator. https://formula.expert/solvers/sound-intensity