Inverse-Square Law for Sound

I=P4πr2I = \frac{P}{4\pi r^{2}}
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Worked example: 100 W at 10 m → I = 1/(4*pi) W/m^2. Press Try an example to run it live, then adjust anything.

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Where Inverse-Square Law for Sound fits

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See also

Sound Intensity (I = P/A): Both use sound intensity and acoustic power.Decibel Sound Level: Both use sound intensity.Apparent Brightness (Inverse-Square Law): Both use distance from source.Distance Attenuation from a Point Source: Both use distance from source.Sound Power Level to Sound Pressure Level: Both use distance from source.Sound Transmission Loss: Both use sound intensity.
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Inverse-Square Law for Sound explained

PrI

Sound from a small source spreads out as an ever-growing sphere, and a sphere's surface area grows as r², so the intensity thins out as 1/r². Double your distance from a firecracker and the intensity drops to a quarter; step back tenfold and it falls a hundredfold: a 20 dB drop. A 0.5 W siren heard from 10 m delivers 0.5/(4π × 100) ≈ 4 × 10⁻⁴ W/m², about 86 dB; from 100 m it is down to 66 dB, no louder than animated conversation.

The law assumes the sound spreads freely in all directions, which is why real environments bend it. A megaphone or a stage horn concentrates power into a cone instead of a sphere, staying loud farther out; a highway heard across open fields behaves more like a line source, fading as 1/r rather than 1/r². Concert engineers exploit the pure form in reverse: measure the intensity at a known distance and the formula reveals the source's total acoustic power.

Inverse-Square Law for Sound formula

I=P4πr2I = \frac{P}{4\pi r^{2}}
Where
  • II= Sound intensity (W/m²)
  • PP= Acoustic power (W)
  • rr= Distance from source (m)
Revised 16 October 2026
Cite this page

formula.expert. (2026, October 16). Inverse-Square Law for Sound Formula & Calculator. https://formula.expert/solvers/inverse-square-intensity