Rope Tension When Lifting a Mass

T=m(g+a)T = m\left(g + a\right)

Worked example: 50 kg hoisted at 2 m/s² → 590.33 N — press Try an example to run it live, then adjust anything.

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Rope Tension When Lifting a Mass explained

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Newton's second law on a hoisted load reads T − mg = ma, so the rope carries T = m(g + a). Lift a 50 kg crate while accelerating upward at 2 m/s² and the rope feels 50 × (9.80665 + 2) ≈ 590 N, about 20% more than the 490 N it holds at rest or at constant speed. Decelerate on the way up — or accelerate downward — and a goes negative, easing the tension; at a = −g the rope goes completely slack and the load is in free fall.

This is exactly why you feel heavy as an elevator starts up and light as it starts down: the floor is the "rope", and the scale under your feet reads m(g + a). Rigging engineers turn the same relation into a dynamic load factor, sizing slings and hooks for the accelerating case rather than the static weight — snatching a load, or an emergency stop, can spike the tension well past the crane's nameplate figure.

Rope Tension When Lifting a Mass formula

T=m(g+a)T = m\left(g + a\right)
Where
  • TT= Rope tension (N)
  • mm= Mass (kg)
  • aa= Upward acceleration (m/s²)

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