Work from Force and Displacement Components
Worked example: F = (12, −5) N through d = (3, 4) m → 16 J. Press Try an example to run it live, then adjust anything.
Enter your known values, leave one input blank, and solves for the missing one. Tap a variable’s symbol to see what it means, with a typical value. Change any unit and the answer follows.
See also
Work–Energy Theorem: Both use work done.Work is a dot product →
Grade 12Grade 12 Math
Test your skills in the Exam Room: new numbers every attempt. Free lessons for students, no sign-up, just pure learning.
Work from Force and Displacement Components explained
Work is the dot product of force and displacement, so in components it is simply Fxdx + Fydy: no angle to measure and no cosine to look up. Each axis contributes independently, and the contributions can cancel: a force of (12, −5) N acting through a displacement of (3, 4) m does 36 − 20 = 16 J of work, the downward pull eating into what the forward push delivered. A component pair that sums to zero means the force was perpendicular to the motion and did no work at all, which is why a satellite in a circular orbit neither gains nor loses energy despite being pulled on the whole way around.
Gaspard-Gustave de Coriolis named the quantity travail in 1829 and fixed the modern convention of force times distance; the joule was attached to it later, honouring James Prescott Joule's paddle-wheel measurements of the mechanical equivalent of heat. The component form makes the sign convention obvious in a way the |F||d| cos θ form does not: negative work simply means the force opposed the motion, exactly what friction and braking do.
Work from Force and Displacement Components formula
- = Work done (J)
- = x-component of force (N)
- = y-component of force (N)
- = x-component of displacement (m)
- = y-component of displacement (m)
Cite this page
formula.expert. (2026, October 16). Work from Force and Displacement Components Calculator. https://formula.expert/solvers/work-from-force-displacement-components