Convert BTU per pound-Fahrenheit to joule per kilogram-kelvin
1 BTU/(lb·°F) = 4,186.8 J/(kg·K)
1 BTU/(lb·°F) = 4,190 J/(kg·K)
1 BTU/(lb·°F) in every specific heat capacity unit
| joule per kilogram-kelvin | 4,190 J/(kg·K) |
| kilojoule per kilogram-kelvin | 4.19 kJ/(kg·K) |
| calorie per gram-Celsius | 1 cal/(g·°C) |
| BTU per pound-Fahrenheit | 1 BTU/(lb·°F) |
How the conversion works
Multiply by 4,186.8 to go from BTU per pound-Fahrenheit to joule per kilogram-kelvin, or divide by it to go back. Every conversion on this site routes through the SI value (J/(kg·K)) rather than a table of pairwise factors, so a round-trip returns exactly what you started with.
Going the other way? joule per kilogram-kelvin to BTU per pound-Fahrenheit — 1 J/(kg·K) = 0.0002388458966 BTU/(lb·°F).
BTU per pound-Fahrenheit to joule per kilogram-kelvin — common values
| 1 BTU/(lb·°F) | 4,186.8 J/(kg·K) |
| 2 BTU/(lb·°F) | 8,373.6 J/(kg·K) |
| 3 BTU/(lb·°F) | 12,560.4 J/(kg·K) |
| 5 BTU/(lb·°F) | 20,934 J/(kg·K) |
| 10 BTU/(lb·°F) | 41,868 J/(kg·K) |
| 15 BTU/(lb·°F) | 62,802 J/(kg·K) |
| 20 BTU/(lb·°F) | 83,736 J/(kg·K) |
| 25 BTU/(lb·°F) | 104,670 J/(kg·K) |
| 50 BTU/(lb·°F) | 209,340 J/(kg·K) |
| 75 BTU/(lb·°F) | 314,010 J/(kg·K) |
| 100 BTU/(lb·°F) | 418,680 J/(kg·K) |
| 250 BTU/(lb·°F) | 1,046,700 J/(kg·K) |
| 500 BTU/(lb·°F) | 2,093,400 J/(kg·K) |
| 1000 BTU/(lb·°F) | 4,186,800 J/(kg·K) |