Convert joule per kilogram-kelvin to BTU per pound-Fahrenheit
1 J/(kg·K) = 0.0002388458966 BTU/(lb·°F)
1 J/(kg·K) = 0.00023885 BTU/(lb·°F)
1 J/(kg·K) in every specific heat capacity unit
| joule per kilogram-kelvin | 1 J/(kg·K) |
| joule per kilogram-Celsius | 1 J/(kg·°C) |
| foot pound-force per pound-Rankine | 0.18586 ft·lbf/(lb·°R) |
| kilojoule per kilogram-kelvin | 0.001 kJ/(kg·K) |
| kilojoule per kilogram-Celsius | 0.001 kJ/(kg·°C) |
| joule per gram-kelvin | 0.001 J/(g·K) |
| calorie per gram-Celsius | 0.00023901 cal/(g·°C) |
| kilocalorie per kilogram-Celsius | 0.00023901 kcal/(kg·°C) |
| BTU per pound-Fahrenheit | 0.00023885 BTU/(lb·°F) |
| BTU per pound-Rankine | 0.00023885 BTU/(lb·°R) |
How the conversion works
Multiply by 0.0002388458966 to go from joule per kilogram-kelvin to BTU per pound-Fahrenheit, or divide by it to go back. Every conversion on this site routes through the SI value (J/(kg·K)) rather than a table of pairwise factors, so a round-trip returns exactly what you started with.
Going the other way? BTU per pound-Fahrenheit to joule per kilogram-kelvin — 1 BTU/(lb·°F) = 4,186.8 J/(kg·K).
joule per kilogram-kelvin to BTU per pound-Fahrenheit — common values
| 1 J/(kg·K) | 0.0002388459 BTU/(lb·°F) |
| 2 J/(kg·K) | 0.00047769179 BTU/(lb·°F) |
| 3 J/(kg·K) | 0.00071653769 BTU/(lb·°F) |
| 5 J/(kg·K) | 0.0011942295 BTU/(lb·°F) |
| 10 J/(kg·K) | 0.002388459 BTU/(lb·°F) |
| 15 J/(kg·K) | 0.0035826884 BTU/(lb·°F) |
| 20 J/(kg·K) | 0.0047769179 BTU/(lb·°F) |
| 25 J/(kg·K) | 0.0059711474 BTU/(lb·°F) |
| 50 J/(kg·K) | 0.011942295 BTU/(lb·°F) |
| 75 J/(kg·K) | 0.017913442 BTU/(lb·°F) |
| 100 J/(kg·K) | 0.02388459 BTU/(lb·°F) |
| 250 J/(kg·K) | 0.059711474 BTU/(lb·°F) |
| 500 J/(kg·K) | 0.11942295 BTU/(lb·°F) |
| 1000 J/(kg·K) | 0.2388459 BTU/(lb·°F) |