Displacement from Average Velocity

Also known as fourth kinematic equation · SUVAT s = ½(u+v)t

d=v0+v2td = \frac{v_0 + v}{2} \, t

Enter your known values, leave one input blank, and solves for the missing one. Try different units for next level excitement!

Learning zone

Under constant acceleration, speed climbs (or falls) in a straight line, so distance covered is just the average of the starting and ending speeds multiplied by the time. A train easing from 30 m/s down to 10 m/s over 20 s travels (30 + 10)/2 × 20 = 400 m. The shortcut fails for non-uniform acceleration, where the simple two-point average no longer represents the whole trip.

Displacement from Average Velocity
d=v0+v2td = \frac{v_0 + v}{2} \, t
Where
  • dd= Displacement
  • v0v_0= Initial velocity
  • vv= Final velocity
  • tt= Time