Conservation of Momentum (Two Bodies)

m1u1+m2u2=m1v1+m2v2m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2

Enter your known values, leave one input blank, and solves for the missing one. Try different units for next level excitement!

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With no external force acting, the total momentum of two colliding bodies before the impact equals the total after — always, whether they bounce, stick, or shatter. Kinetic energy is not so obliging; it survives only in a perfectly elastic collision. The principle was nailed down in 1668 when the Royal Society set the collision problem as a challenge and John Wallis, Christopher Wren and Christiaan Huygens independently sent in the answer.

Signs are everything in one dimension: pick a positive direction and stick with it, so a body moving the other way carries a negative velocity. A 2 kg cart at 5 m/s striking a stationary 3 kg cart and slowing to 1 m/s leaves the second cart at (10 + 0 − 2) ⁄ 3 ≈ 2.67 m/s. Because momentum is conserved in every collision, crash investigators use exactly this equation with skid-mark evidence to back out pre-impact speeds, and it works equally well for recoil: the rifle and the bullet start with zero total momentum and must end with zero.

Conservation of Momentum (Two Bodies)
m1u1+m2u2=m1v1+m2v2m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2
Where
  • m1m_1= Mass 1
  • u1u_1= Initial velocity 1
  • m2m_2= Mass 2
  • u2u_2= Initial velocity 2
  • v1v_1= Final velocity 1
  • v2v_2= Final velocity 2