Conservation of Momentum (Two Bodies)

m1u1+m2u2=m1v1+m2v2m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2
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Worked example: 2 kg at 5 m/s into 3 kg at rest → v2 = 2.667 m/s. Press Try an example to run it live, then adjust anything.

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Elastic Collision: Final Velocity of Body 1: Both use object mass and initial velocity.Perfectly Inelastic Collision: Both use object mass and initial velocity.Coefficient of Restitution: Both use initial velocity and final velocity.
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Conservation of Momentum (Two Bodies) explained

m1u1m2u2v1v2

With no external force acting, the total momentum of two colliding bodies before the impact equals the total after: always, whether they bounce, stick, or shatter. Kinetic energy is not so obliging; it survives only in a perfectly elastic collision. The principle was nailed down in 1668 when the Royal Society set the collision problem as a challenge and John Wallis, Christopher Wren and Christiaan Huygens independently sent in the answer.

Signs are everything in one dimension: pick a positive direction and stick with it, so a body moving the other way carries a negative velocity. A 2 kg cart at 5 m/s striking a stationary 3 kg cart and slowing to 1 m/s leaves the second cart at (10 + 0 − 2) ⁄ 3 ≈ 2.67 m/s. Because momentum is conserved in every collision, crash investigators use exactly this equation with skid-mark evidence to back out pre-impact speeds, and it works equally well for recoil: the rifle and the bullet start with zero total momentum and must end with zero.

Conservation of Momentum (Two Bodies) formula

m1u1+m2u2=m1v1+m2v2m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2
Where
  • m1m_1= Mass 1 (kg)
  • u1u_1= Initial velocity 1 (m/s)
  • m2m_2= Mass 2 (kg)
  • u2u_2= Initial velocity 2 (m/s)
  • v1v_1= Final velocity 1 (m/s)
  • v2v_2= Final velocity 2 (m/s)
Revised 16 October 2026
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formula.expert. (2026, October 16). Conservation of Momentum (Two Bodies) Formula & Calculator. https://formula.expert/solvers/momentum-conservation-two-bodies