Poiseuille's Law

Q=πΔPr48μLQ = \frac{\pi \, \Delta P \, r^{4}}{8 \mu L}

Enter your known values, leave one input blank, and solves for the missing one. Try different units for next level excitement!

Learning zone

For smooth laminar flow, the throughput of a pipe rises with the fourth power of its radius: double the bore and you pass sixteen times the flow for the same pressure. Nowhere does this matter more than in your arteries — a 10% narrowing costs about a third of the flow, which is why small plaques have outsized consequences and why vasodilation is such a powerful regulator.

The same r⁴ tyranny governs hypodermic needles, inkjet nozzles, and microfluidic chips, where halving a channel's width demands sixteen times the driving pressure.

Poiseuille's Law
Q=πΔPr48μLQ = \frac{\pi \, \Delta P \, r^{4}}{8 \mu L}
Where
  • QQ= Volumetric flow rate
  • ΔP\Delta P= Pressure drop
  • rr= Pipe radius
  • μ\mu= Dynamic viscosity
  • LL= Pipe length