Weymouth Gas Pipeline Flow (Flow from the Pressure Drop)
Also known as Weymouth equation · gas pipeline flow equation · high pressure gas flow in a pipe · gas gathering line flow · natural gas pipeline capacity · pipeline flow from inlet and outlet pressure · gas flow through a pipeline · Weymouth formula · gas transmission flow equation · pipeline pressure drop for gas · 433.5 Weymouth
Worked example: the same example in Menon's SI form (kPa, km, mm, m3/d) → 6.5240 MPa out. Press Try an example to run it live, then adjust anything.
Enter your known values, leave one input blank, and solves for the missing one. Tap a variable’s symbol to see what it means, with a typical value. Change any unit and the answer follows.
Where Weymouth Gas Pipeline Flow (Flow from the Pressure Drop) fits
Weymouth Gas Pipeline Flow (Flow from the Pressure Drop) explained
The Weymouth equation answers a practical question about a gas line: given the pressure at the inlet and at the outlet, how much gas moves through the pipe? The flow is stated at base conditions, a base temperature and a base pressure , so it is the volume the gas would fill if it were brought to those conditions, not the volume passing a point in the pipe, where the gas is compressed and takes up less room. The pressures enter as , and both must be absolute: a gauge reading gives the wrong answer.
The other terms each have a plain meaning. The flow falls with the gas gravity , the flowing temperature , the length and the compressibility factor : a heavier gas, a warmer gas, a longer pipe and a larger compressibility factor all reduce the flow for the same fall in pressure. It rises very steeply with the inside diameter, as , so a small change in diameter changes the flow a great deal. The efficiency , from 0.92 to 1.00, allows for a pipe rougher or dirtier than new. Weymouth has no friction factor of its own; it assumes one that falls with the diameter. In Menon's worked example it gives a larger pressure drop than the Panhandle equations for the same flow, so its answer is the more conservative.
The equation is T. R. Weymouth's of 1912, written for high-pressure gas gathering lines. This page follows E. S. Menon's Gas Pipeline Hydraulics and his course text, which print the constant as 433.5 in US customary units and as 3.7435e-3 in an SI form (cubic metres a day, kilopascals, kilometres, millimetres). The page accepts any unit and converts exactly, which leaves 137.34 in SI base units. The elevation term of the full equation is left out, so the pipe is taken as level.
The worked example is Menon's example 11: an NPS 18 line with 17.5 in inside diameter, 20 miles long, carrying 150 MMSCFD of gas of gravity 0.6 at 70 °F, with , , base conditions of 60 °F and 14.7 psia, and an inlet pressure of 1 000 psig (1 014.7 psia). Menon finds an outlet pressure of 946.24 psia. The page's example enters the same case in his SI form and returns 6.5240 MPa out, within 1e-5 of the US form. Run backwards from the printed outlet pressure, it returns the diameter 17.5 in, the length 20 miles and the efficiency 0.95.
Weymouth Gas Pipeline Flow (Flow from the Pressure Drop) formula
- = Gas flow at base conditions (m³/d)
- = Pipeline efficiency
- = Base temperature (°C)
- = Base pressure (kPa)
- = Inlet pressure (absolute) (MPa)
- = Outlet pressure (absolute) (MPa)
- = Gas gravity (air = 1)
- = Mean flowing temperature (°C)
- = Pipeline length (km)
- = Compressibility factor
- = Inside diameter (mm)
- Weymouth, T. R. (1912). Problems in natural gas engineering. Transactions of the American Society of Mechanical Engineers, 34, 185-231 (the original equation for the flow of gas in high-pressure lines; the DOI record was checked in Crossref, the paper itself was not opened here). Read it
- Menon, E. S. (2005). Gas Pipeline Hydraulics. CRC Press, Boca Raton (the Weymouth, Panhandle and general flow equations with their constants in both unit systems; the DOI record was checked in Crossref, the book was not opened here). Read it
- Menon, E. S., Gas Pipeline Hydraulics, course P06-001, CED Engineering (the same author's course text), read 23 Oct 2026: equation 2.30, the Weymouth equation in US customary units, Q = 433.5 E (Tb/Pb) [(P1^2 - e^s P2^2) / (G Tf Le Z)]^0.5 D^2.667, with Q in standard cubic feet a day, temperatures in degrees Rankine, pressures in psia, length in miles and diameter in inches; equation 2.32, the SI form, with 3.7435e-3, Q in m3/day, pressures in kPa, length in km and diameter in mm; equations 2.31 and 2.33, the Weymouth transmission factors 11.18 D^(1/6) and 6.521 D^(1/6); and example 11, a 20-mile NPS 18 line (17.5 in inside diameter) carrying 150 MMSCFD with an inlet pressure of 1 000 psig (1 014.7 psia), gas gravity 0.6, 70 degrees Fahrenheit, Z 0.85 and efficiency 0.95 at base conditions of 60 degrees Fahrenheit and 14.7 psia, which gives an outlet pressure of 946.24 psia by the Weymouth equation. Read it
Cite this page
formula.expert. (2026, October 30). Weymouth Gas Pipeline Flow (Flow from the Pressure Drop) Calculator. https://formula.expert/solvers/weymouth-gas-pipeline-flow