Acceleration Down a Frictionless Incline

a=gsin⁡θa = g \sin\theta

Worked example: 30° frictionless ramp → 4.9033 m/s² — press Try an example to run it live, then adjust anything.

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Sliding down →

Grade 12Grade 12 Physics

Down the incline →

UniversityEngineering Mechanics

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Acceleration Down a Frictionless Incline explained

aθ

Strip friction away and the down-slope force mg sin θ divided by the mass m leaves a = g sin θ — the mass cancels completely, so a marble and a bowling ball slide identically. A 30° ramp yields 9.80665 × 0.5 ≈ 4.90 m/s², exactly half of free fall. This is Galileo's "diluted gravity": by 1604 he had shown that distances on an incline still grow as t², and he extrapolated to θ = 90°, where a = g and the ramp becomes free fall.

Watch the assumption — sliding, not rolling. A ball that rolls without slipping must also spin up its own moment of inertia, so a solid sphere manages only (5/7)g sin θ and a hoop just (1/2)g sin θ. That difference is the whole point of the classic race down a ramp, where a solid cylinder always beats a hollow one of identical mass and radius.

Acceleration Down a Frictionless Incline formula

a=gsin⁡θa = g \sin\theta
Where
  • aa= Acceleration (m/s²)
  • θ\theta= Incline angle (°)