Escape Velocity of the Earth

vesc,=11,186 m/sv_{\mathrm{esc},\oplus} = 11,186\ \text{m/s}
Value11,186 m/s
StatusConventional / typical value
SourceDerived from GM⊕ and the IUGG mean radius
CategoriesAstronomicalearthorbital-mechanics
v_esc_earth in every speed unit
meter per second11,186 m/s
kilometer per hour40,269.6 km/h
foot per second36,699.475 ft/s
mile per hour25,022.369 mph
knot21,743.844 kn
foot per minute2,201,968.5 ft/min
centimeter per second1,118,600 cm/s
meter per hour40,269,600 m/h
meter per day966,470,400 m/d
foot per day3,170,834,600 ft/d

Learning zone

From √(2GM⊕/R) with the mean radius, escape velocity is 11.19 km/s — Mach 33, and exactly √2 times the 7.91 km/s needed merely to circle the planet at the surface. No chemical rocket reaches it in a single impulsive burn; launchers climb gradually while fighting gravity and drag losses, so the real delta-v to escape from the ground is closer to 13–14 km/s. Launching eastward near the equator gets you up to 0.46 km/s of it for free from Earth's rotation, which is why Kourou and Cape Canaveral are where they are.

Escape velocity also governs what an atmosphere can keep. Molecules in the high-temperature exosphere follow a Maxwell–Boltzmann distribution, and any species whose typical thermal speed climbs within about a sixth of escape velocity leaks away over geological time — which is why Earth retains nitrogen, oxygen and water vapour but has lost essentially all of its primordial hydrogen and helium.